((4x^2+2x+8)/2)

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Solution for ((4x^2+2x+8)/2) equation: 


x in (-oo:+oo)

(4*x^2+2*x+8)/2 = 0

4*x^2+2*x+8 = 0

2*(2*x^2+x+4) = 0

2*x^2+x+4 = 0

DELTA = 1^2-(2*4*4)

DELTA = -31

DELTA < 0

2 = 0

1 = 0

x belongs to the empty set

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